Thanks to all that responded to my previous thread. There is still a problem with this simple program that I would like to solve. I am trying to import one class into another as a member object. The output of this program is confusing, though. As a test of the code, I output the scalar contained within the first class object. This works. Then I output the scalar the is contained in the object contained as a member of the second class, and this outputs zero. I assume that something is wrong. Could someone shed some light on this problem? Thanks!
#include <iostream>
using namespace std;
typedef double* doublevec;
// This first class contains a vector and a scalar representing the size of the vector.
typedef class Structure1
{
int N;
doublevec vec;
public:
// Constructor and copy constructor.
Structure1(int Nin);
Structure1(const Structure1& structurein);
// Accessor functions:
int get_N() { return N; }
doublevec get_vec() { return vec; }
// Destructor:
~Structure1() { delete []vec; }
} Structure1;
Structure1::Structure1(int Nin)
{
N = Nin;
vec = new double [N];
for (int i = 0; i < N; i++)
{
vec[i] = i;
};
}
Structure1::Structure1(const Structure1& structurein)
{
vec = new double[structurein.N];
for(int i = 0; i < structurein.N; i++)
{
vec[i] = structurein.vec[i];
};
}
// This class just contains the first structure.
typedef class Structure2
{
Structure1 structure;
public:
// Constructor:
Structure2(const Structure1& structurein) : structure(structurein) {}
// Accessor Function:
Structure1 get_structure() { return structure; }
// Destructor:
~Structure2() {}
} Structure2;
int main (int argc, char * const argv[])
{
const int N = 100;
Structure1 structure1(N);
Structure2 structure2(structure1);
cout << structure1.get_N() << endl;
cout << structure2.get_structure().get_N();
return 0;
}
-
Looks like you don't set
NinStructure1's copy constructor. You need:Structure1::Structure1(const Structure1& structurein){ N = structurein.N; vec = new double[structurein.N]; for(int i = 0; i < structurein.N; i++) { vec[i] = structurein.vec[i]; } }(Also, you don't need a semicolon after a for-loop. But that's another matter.)
Edit: This was actually mentioned in an answer to your other question. ;)
Michael Myers : Funny thing is that I don't even know C++ all that well; but I do know how to debug. -
This has nothing to do with the question, that has been properly answered by mmyers (and already accepted), but since it seems that you are learning, just a couple of advices:
You do not need typedefs for structs or classes, the typename will automatically be available in the namespace. [*]
Make 1 argument constructors explicit and prefer initialization lists to code in the constructor block. Marking explicit will avoid implicit casts from the argument type to the class type.
Constness is important: Mark non-mutating methods as const so that the compiler knows.
Prefer libraries over hand made equivalent solutions. Know the STL (std::vector is probably quite similar to what you are working on, now I understand this is probably for learning)
class Structure1 // typedef removed { int N; double *vec; public: explicit Structure1( int Nin ); // explicit to disable implicit conversions from int to Structure1 Structure1( const Structure1 & stin ); int get_N() const { return N; } // marked as const: it won't change the object double* get_vector() { return vec; } // not const: user can change the contents of the vector! // if you don't want the user to change it return a const double* }; Structure1::Structure1( int Nin ) : N( Nin ), vec( new double[Nin] ) { for ( int i = 0; i < N; ++i ) vec[i] = i; } Structure1::Structure1( const Structure1 & other ) : N( other.N ), vec( new double[other.N] ) { for ( int i = 0; i < N; ++i ) vec[i] = other.vec[i]; }[*] There is a subtle difference, but it won't show up in 99.99% of the code and most C++ programmers don't even know. Most people are used to not typedef-ing classes or structs in C++.
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